3.2980 \(\int \frac{(2+3 x)^{11/2}}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx\)

Optimal. Leaf size=218 \[ -\frac{11346991 \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right ),\frac{35}{33}\right )}{378125 \sqrt{33}}+\frac{7 (3 x+2)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{5 x+3}}-\frac{896 (3 x+2)^{7/2}}{363 \sqrt{1-2 x} \sqrt{5 x+3}}+\frac{4439 \sqrt{1-2 x} (3 x+2)^{5/2}}{19965 \sqrt{5 x+3}}-\frac{932783 \sqrt{1-2 x} \sqrt{5 x+3} (3 x+2)^{3/2}}{332750}-\frac{21713939 \sqrt{1-2 x} \sqrt{5 x+3} \sqrt{3 x+2}}{1663750}-\frac{1508889271 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{1512500 \sqrt{33}} \]

[Out]

(4439*Sqrt[1 - 2*x]*(2 + 3*x)^(5/2))/(19965*Sqrt[3 + 5*x]) - (896*(2 + 3*x)^(7/2))/(363*Sqrt[1 - 2*x]*Sqrt[3 +
5*x]) + (7*(2 + 3*x)^(9/2))/(33*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) - (21713939*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*Sqrt[3
+ 5*x])/1663750 - (932783*Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*Sqrt[3 + 5*x])/332750 - (1508889271*EllipticE[ArcSin[
Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/(1512500*Sqrt[33]) - (11346991*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35
/33])/(378125*Sqrt[33])

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Rubi [A]  time = 0.0813794, antiderivative size = 218, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.214, Rules used = {98, 150, 154, 158, 113, 119} \[ \frac{7 (3 x+2)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{5 x+3}}-\frac{896 (3 x+2)^{7/2}}{363 \sqrt{1-2 x} \sqrt{5 x+3}}+\frac{4439 \sqrt{1-2 x} (3 x+2)^{5/2}}{19965 \sqrt{5 x+3}}-\frac{932783 \sqrt{1-2 x} \sqrt{5 x+3} (3 x+2)^{3/2}}{332750}-\frac{21713939 \sqrt{1-2 x} \sqrt{5 x+3} \sqrt{3 x+2}}{1663750}-\frac{11346991 F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{378125 \sqrt{33}}-\frac{1508889271 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{1512500 \sqrt{33}} \]

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)^(11/2)/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

(4439*Sqrt[1 - 2*x]*(2 + 3*x)^(5/2))/(19965*Sqrt[3 + 5*x]) - (896*(2 + 3*x)^(7/2))/(363*Sqrt[1 - 2*x]*Sqrt[3 +
5*x]) + (7*(2 + 3*x)^(9/2))/(33*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x]) - (21713939*Sqrt[1 - 2*x]*Sqrt[2 + 3*x]*Sqrt[3
+ 5*x])/1663750 - (932783*Sqrt[1 - 2*x]*(2 + 3*x)^(3/2)*Sqrt[3 + 5*x])/332750 - (1508889271*EllipticE[ArcSin[
Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/(1512500*Sqrt[33]) - (11346991*EllipticF[ArcSin[Sqrt[3/7]*Sqrt[1 - 2*x]], 35
/33])/(378125*Sqrt[33])

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 150

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[((b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && LtQ[m, -1] && GtQ[n, 0] && IntegersQ[2*m, 2*n, 2*p]

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 158

Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol]
:> Dist[h/f, Int[Sqrt[e + f*x]/(Sqrt[a + b*x]*Sqrt[c + d*x]), x], x] + Dist[(f*g - e*h)/f, Int[1/(Sqrt[a + b*
x]*Sqrt[c + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && SimplerQ[a + b*x, e + f*x] &&
SimplerQ[c + d*x, e + f*x]

Rule 113

Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-((b*e
- a*f)/d), 2]*EllipticE[ArcSin[Sqrt[a + b*x]/Rt[-((b*c - a*d)/d), 2]], (f*(b*c - a*d))/(d*(b*e - a*f))])/b, x
] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !LtQ[-((b*c - a*d)/d),
0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-(d/(b*c - a*d)), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)
/b, 0])

Rule 119

Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x_)]), x_Symbol] :> Simp[(2*Rt[-(b/d
), 2]*EllipticF[ArcSin[Sqrt[a + b*x]/(Rt[-(b/d), 2]*Sqrt[(b*c - a*d)/b])], (f*(b*c - a*d))/(d*(b*e - a*f))])/(
b*Sqrt[(b*e - a*f)/b]), x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ[(b*e - a*f)/b, 0] &
& PosQ[-(b/d)] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d*e - c*f)/d, 0] && GtQ[-(d/b), 0]) &&  !(SimplerQ[c +
d*x, a + b*x] && GtQ[(-(b*e) + a*f)/f, 0] && GtQ[-(f/b), 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ[(-(d*e)
+ c*f)/f, 0] && GtQ[(-(b*e) + a*f)/f, 0] && (PosQ[-(f/d)] || PosQ[-(f/b)]))

Rubi steps

\begin{align*} \int \frac{(2+3 x)^{11/2}}{(1-2 x)^{5/2} (3+5 x)^{3/2}} \, dx &=\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{1}{33} \int \frac{(2+3 x)^{7/2} \left (\frac{485}{2}+411 x\right )}{(1-2 x)^{3/2} (3+5 x)^{3/2}} \, dx\\ &=-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{1}{363} \int \frac{\left (-23785-\frac{80763 x}{2}\right ) (2+3 x)^{5/2}}{\sqrt{1-2 x} (3+5 x)^{3/2}} \, dx\\ &=\frac{4439 \sqrt{1-2 x} (2+3 x)^{5/2}}{19965 \sqrt{3+5 x}}-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{2 \int \frac{\left (-\frac{1710201}{4}-\frac{2798349 x}{4}\right ) (2+3 x)^{3/2}}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{19965}\\ &=\frac{4439 \sqrt{1-2 x} (2+3 x)^{5/2}}{19965 \sqrt{3+5 x}}-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{932783 \sqrt{1-2 x} (2+3 x)^{3/2} \sqrt{3+5 x}}{332750}+\frac{2 \int \frac{\sqrt{2+3 x} \left (\frac{240978825}{8}+\frac{195425451 x}{4}\right )}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{499125}\\ &=\frac{4439 \sqrt{1-2 x} (2+3 x)^{5/2}}{19965 \sqrt{3+5 x}}-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{21713939 \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}}{1663750}-\frac{932783 \sqrt{1-2 x} (2+3 x)^{3/2} \sqrt{3+5 x}}{332750}-\frac{2 \int \frac{-\frac{8597342907}{8}-\frac{13580003439 x}{8}}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx}{7486875}\\ &=\frac{4439 \sqrt{1-2 x} (2+3 x)^{5/2}}{19965 \sqrt{3+5 x}}-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{21713939 \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}}{1663750}-\frac{932783 \sqrt{1-2 x} (2+3 x)^{3/2} \sqrt{3+5 x}}{332750}+\frac{11346991 \int \frac{1}{\sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}} \, dx}{756250}+\frac{1508889271 \int \frac{\sqrt{3+5 x}}{\sqrt{1-2 x} \sqrt{2+3 x}} \, dx}{16637500}\\ &=\frac{4439 \sqrt{1-2 x} (2+3 x)^{5/2}}{19965 \sqrt{3+5 x}}-\frac{896 (2+3 x)^{7/2}}{363 \sqrt{1-2 x} \sqrt{3+5 x}}+\frac{7 (2+3 x)^{9/2}}{33 (1-2 x)^{3/2} \sqrt{3+5 x}}-\frac{21713939 \sqrt{1-2 x} \sqrt{2+3 x} \sqrt{3+5 x}}{1663750}-\frac{932783 \sqrt{1-2 x} (2+3 x)^{3/2} \sqrt{3+5 x}}{332750}-\frac{1508889271 E\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{1512500 \sqrt{33}}-\frac{11346991 F\left (\sin ^{-1}\left (\sqrt{\frac{3}{7}} \sqrt{1-2 x}\right )|\frac{35}{33}\right )}{378125 \sqrt{33}}\\ \end{align*}

Mathematica [A]  time = 0.282548, size = 107, normalized size = 0.49 \[ \frac{-759987865 \text{EllipticF}\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right ),-\frac{33}{2}\right )-\frac{5 \sqrt{6 x+4} \left (48514950 x^4+286777260 x^3-1463754851 x^2-376752444 x+356556921\right )}{(1-2 x)^{3/2} \sqrt{5 x+3}}[phone] E\left (\sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )|-\frac{33}{2}\right )}{24956250 \sqrt{2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)^(11/2)/((1 - 2*x)^(5/2)*(3 + 5*x)^(3/2)),x]

[Out]

((-5*Sqrt[4 + 6*x]*(356556921 - 376752444*x - 1463754851*x^2 + 286777260*x^3 + 48514950*x^4))/((1 - 2*x)^(3/2)
*Sqrt[3 + 5*x]) + 1508889271*EllipticE[ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]], -33/2] - 759987865*EllipticF[ArcSin[S
qrt[2/11]*Sqrt[3 + 5*x]], -33/2])/(24956250*Sqrt[2])

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Maple [C]  time = 0.024, size = 238, normalized size = 1.1 \begin{align*}{\frac{1}{49912500\, \left ( 2\,x-1 \right ) ^{2} \left ( 15\,{x}^{2}+19\,x+6 \right ) }\sqrt{1-2\,x}\sqrt{2+3\,x}\sqrt{3+5\,x} \left ( 1519975730\,\sqrt{2}{\it EllipticF} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) x\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}-3017778542\,\sqrt{2}{\it EllipticE} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) x\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}-759987865\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticF} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) [phone]\,\sqrt{2}\sqrt{3+5\,x}\sqrt{2+3\,x}\sqrt{1-2\,x}{\it EllipticE} \left ( 1/11\,\sqrt{66+110\,x},i/2\sqrt{66} \right ) -1455448500\,{x}^{5}-9573616800\,{x}^{4}[phone]\,{x}^{3}[phone]\,{x}^{2}-3161658750\,x-7131138420 \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)^(11/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x)

[Out]

1/49912500*(2+3*x)^(1/2)*(1-2*x)^(1/2)*(3+5*x)^(1/2)*(1519975730*2^(1/2)*EllipticF(1/11*(66+110*x)^(1/2),1/2*I
*66^(1/2))*x*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)-3017778542*2^(1/2)*EllipticE(1/11*(66+110*x)^(1/2),1/2*
I*66^(1/2))*x*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(1/2)-759987865*2^(1/2)*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^
(1/2)*EllipticF(1/11*(66+110*x)^(1/2),1/2*I*66^(1/2))[phone]*2^(1/2)*(3+5*x)^(1/2)*(2+3*x)^(1/2)*(1-2*x)^(
1/2)*EllipticE(1/11*(66+110*x)^(1/2),1/2*I*66^(1/2))-1455448500*x^5-9573616800*x^4+38177100330*x^3+40577670340
*x^2-3161658750*x-7131138420)/(2*x-1)^2/(15*x^2+19*x+6)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (3 \, x + 2\right )}^{\frac{11}{2}}}{{\left (5 \, x + 3\right )}^{\frac{3}{2}}{\left (-2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

integrate((3*x + 2)^(11/2)/((5*x + 3)^(3/2)*(-2*x + 1)^(5/2)), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )} \sqrt{5 \, x + 3} \sqrt{3 \, x + 2} \sqrt{-2 \, x + 1}}{200 \, x^{5} - 60 \, x^{4} - 138 \, x^{3} + 47 \, x^{2} + 24 \, x - 9}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

integral(-(243*x^5 + 810*x^4 + 1080*x^3 + 720*x^2 + 240*x + 32)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1)/(20
0*x^5 - 60*x^4 - 138*x^3 + 47*x^2 + 24*x - 9), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**(11/2)/(1-2*x)**(5/2)/(3+5*x)**(3/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (3 \, x + 2\right )}^{\frac{11}{2}}}{{\left (5 \, x + 3\right )}^{\frac{3}{2}}{\left (-2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^(11/2)/(1-2*x)^(5/2)/(3+5*x)^(3/2),x, algorithm="giac")

[Out]

integrate((3*x + 2)^(11/2)/((5*x + 3)^(3/2)*(-2*x + 1)^(5/2)), x)